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7(x+5)=2(4-x)
We move all terms to the left:
7(x+5)-(2(4-x))=0
We add all the numbers together, and all the variables
7(x+5)-(2(-1x+4))=0
We multiply parentheses
7x-(2(-1x+4))+35=0
We calculate terms in parentheses: -(2(-1x+4)), so:We get rid of parentheses
2(-1x+4)
We multiply parentheses
-2x+8
Back to the equation:
-(-2x+8)
7x+2x-8+35=0
We add all the numbers together, and all the variables
9x+27=0
We move all terms containing x to the left, all other terms to the right
9x=-27
x=-27/9
x=-3
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