7(x+5)=2(x+35)

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Solution for 7(x+5)=2(x+35) equation:


Simplifying
7(x + 5) = 2(x + 35)

Reorder the terms:
7(5 + x) = 2(x + 35)
(5 * 7 + x * 7) = 2(x + 35)
(35 + 7x) = 2(x + 35)

Reorder the terms:
35 + 7x = 2(35 + x)
35 + 7x = (35 * 2 + x * 2)
35 + 7x = (70 + 2x)

Solving
35 + 7x = 70 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
35 + 7x + -2x = 70 + 2x + -2x

Combine like terms: 7x + -2x = 5x
35 + 5x = 70 + 2x + -2x

Combine like terms: 2x + -2x = 0
35 + 5x = 70 + 0
35 + 5x = 70

Add '-35' to each side of the equation.
35 + -35 + 5x = 70 + -35

Combine like terms: 35 + -35 = 0
0 + 5x = 70 + -35
5x = 70 + -35

Combine like terms: 70 + -35 = 35
5x = 35

Divide each side by '5'.
x = 7

Simplifying
x = 7

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