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7(x+5)=6(x-3)
We move all terms to the left:
7(x+5)-(6(x-3))=0
We multiply parentheses
7x-(6(x-3))+35=0
We calculate terms in parentheses: -(6(x-3)), so:We get rid of parentheses
6(x-3)
We multiply parentheses
6x-18
Back to the equation:
-(6x-18)
7x-6x+18+35=0
We add all the numbers together, and all the variables
x+53=0
We move all terms containing x to the left, all other terms to the right
x=-53
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