7(x-1)+1=3(x+1)-8

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Solution for 7(x-1)+1=3(x+1)-8 equation: 



7(x-1)+1=3(x+1)-8

We move all terms to the left:

7(x-1)+1-(3(x+1)-8)=0

We multiply parentheses

7x-(3(x+1)-8)-7+1=0



We calculate terms in parentheses: -(3(x+1)-8), so:

3(x+1)-8

We multiply parentheses

3x+3-8

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

7x-(3x-5)-6=0

We get rid of parentheses

7x-3x+5-6=0

We add all the numbers together, and all the variables

4x-1=0

We move all terms containing x to the left, all other terms to the right

4x=1

x=1/4

x=1/4

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