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7(x-1)+2(3x+7)=3(4x+1)
We move all terms to the left:
7(x-1)+2(3x+7)-(3(4x+1))=0
We multiply parentheses
7x+6x-(3(4x+1))-7+14=0
We calculate terms in parentheses: -(3(4x+1)), so:We add all the numbers together, and all the variables
3(4x+1)
We multiply parentheses
12x+3
Back to the equation:
-(12x+3)
13x-(12x+3)+7=0
We get rid of parentheses
13x-12x-3+7=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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