7(x-1)+2x=1/4(x+3)+1

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Solution for 7(x-1)+2x=1/4(x+3)+1 equation: 



7(x-1)+2x=1/4(x+3)+1

We move all terms to the left:

7(x-1)+2x-(1/4(x+3)+1)=0



Domain of the equation: 4(x+3)+1)!=0

x∈R



We add all the numbers together, and all the variables

2x+7(x-1)-(1/4(x+3)+1)=0

We multiply parentheses

2x+7x-(1/4(x+3)+1)-7=0

We multiply all the terms by the denominator


2x*4(x+3)+1)+7x*4(x+3)+1)-(1-7*4(x+3)+1)=0

We add all the numbers together, and all the variables

2x*4(x+3)+1)+7x*4(x+3)+1)-(1-7*4(x=0

Wy multiply elements

8x^2(x+1)+7x*4(x+3)-7*4(x+1)-(1=0

We add all the numbers together, and all the variables

8x^2(x+1)+7x*4(x+3)-7*4(x+1)=0

Wy multiply elements

8x^2(x+1)+28x^2(x-28x(x=0

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