7(x-1)+4=-(2x-4)+(6x+2)

Solution for 7(x-1)+4=-(2x-4)+(6x+2) equation:

7(x-1)+4=-(2x-4)+(6x+2)

We move all terms to the left:

7(x-1)+4-(-(2x-4)+(6x+2))=0

We multiply parentheses

7x-(-(2x-4)+(6x+2))-7+4=0


We calculate terms in parentheses: -(-(2x-4)+(6x+2)), so:

-(2x-4)+(6x+2)

We get rid of parentheses

-2x+6x+4+2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)


We add all the numbers together, and all the variables

7x-(4x+6)-3=0

We get rid of parentheses

7x-4x-6-3=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3