7(x-1)+4=-(2x-4)+(6x+2)

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Solution for 7(x-1)+4=-(2x-4)+(6x+2) equation:



7(x-1)+4=-(2x-4)+(6x+2)
We move all terms to the left:
7(x-1)+4-(-(2x-4)+(6x+2))=0
We multiply parentheses
7x-(-(2x-4)+(6x+2))-7+4=0
We calculate terms in parentheses: -(-(2x-4)+(6x+2)), so:
-(2x-4)+(6x+2)
We get rid of parentheses
-2x+6x+4+2
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
We add all the numbers together, and all the variables
7x-(4x+6)-3=0
We get rid of parentheses
7x-4x-6-3=0
We add all the numbers together, and all the variables
3x-9=0
We move all terms containing x to the left, all other terms to the right
3x=9
x=9/3
x=3

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