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7(x-1)+8=3x+4(1+x)
We move all terms to the left:
7(x-1)+8-(3x+4(1+x))=0
We add all the numbers together, and all the variables
7(x-1)-(3x+4(x+1))+8=0
We multiply parentheses
7x-(3x+4(x+1))-7+8=0
We calculate terms in parentheses: -(3x+4(x+1)), so:We add all the numbers together, and all the variables
3x+4(x+1)
We multiply parentheses
3x+4x+4
We add all the numbers together, and all the variables
7x+4
Back to the equation:
-(7x+4)
7x-(7x+4)+1=0
We get rid of parentheses
7x-7x-4+1=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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