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7(x-1)-2(x-6)=2(x-5)+3
We move all terms to the left:
7(x-1)-2(x-6)-(2(x-5)+3)=0
We multiply parentheses
7x-2x-(2(x-5)+3)-7+12=0
We calculate terms in parentheses: -(2(x-5)+3), so:We add all the numbers together, and all the variables
2(x-5)+3
We multiply parentheses
2x-10+3
We add all the numbers together, and all the variables
2x-7
Back to the equation:
-(2x-7)
5x-(2x-7)+5=0
We get rid of parentheses
5x-2x+7+5=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4
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