7(x-1)-5=-3(-8x+2)-8x

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Solution for 7(x-1)-5=-3(-8x+2)-8x equation: 



7(x-1)-5=-3(-8x+2)-8x

We move all terms to the left:

7(x-1)-5-(-3(-8x+2)-8x)=0

We multiply parentheses

7x-(-3(-8x+2)-8x)-7-5=0



We calculate terms in parentheses: -(-3(-8x+2)-8x), so:

-3(-8x+2)-8x

We add all the numbers together, and all the variables

-8x-3(-8x+2)

We multiply parentheses

-8x+24x-6

We add all the numbers together, and all the variables

16x-6

Back to the equation:

-(16x-6)



We add all the numbers together, and all the variables

7x-(16x-6)-12=0

We get rid of parentheses

7x-16x+6-12=0

We add all the numbers together, and all the variables

-9x-6=0

We move all terms containing x to the left, all other terms to the right

-9x=6

x=6/-9

x=-2/3

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