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7(x-1)=2(3+x)
We move all terms to the left:
7(x-1)-(2(3+x))=0
We add all the numbers together, and all the variables
7(x-1)-(2(x+3))=0
We multiply parentheses
7x-(2(x+3))-7=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
7x-2x-6-7=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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