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7(x-1)=3(2x+1)
We move all terms to the left:
7(x-1)-(3(2x+1))=0
We multiply parentheses
7x-(3(2x+1))-7=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
7x-6x-3-7=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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