7(x-12)=4(x+12)

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Solution for 7(x-12)=4(x+12) equation: 



7(x-12)=4(x+12)

We move all terms to the left:

7(x-12)-(4(x+12))=0

We multiply parentheses

7x-(4(x+12))-84=0



We calculate terms in parentheses: -(4(x+12)), so:

4(x+12)

We multiply parentheses

4x+48

Back to the equation:

-(4x+48)



We get rid of parentheses

7x-4x-48-84=0

We add all the numbers together, and all the variables

3x-132=0

We move all terms containing x to the left, all other terms to the right

3x=132

x=132/3

x=44

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