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7(x-2)+5=3(2x-1)
We move all terms to the left:
7(x-2)+5-(3(2x-1))=0
We multiply parentheses
7x-(3(2x-1))-14+5=0
We calculate terms in parentheses: -(3(2x-1)), so:We add all the numbers together, and all the variables
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
7x-(6x-3)-9=0
We get rid of parentheses
7x-6x+3-9=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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