7(x-2)+6x=3(-2+x)+10

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Solution for 7(x-2)+6x=3(-2+x)+10 equation: 



7(x-2)+6x=3(-2+x)+10

We move all terms to the left:

7(x-2)+6x-(3(-2+x)+10)=0

We add all the numbers together, and all the variables

7(x-2)+6x-(3(x-2)+10)=0

We add all the numbers together, and all the variables

6x+7(x-2)-(3(x-2)+10)=0

We multiply parentheses

6x+7x-(3(x-2)+10)-14=0



We calculate terms in parentheses: -(3(x-2)+10), so:

3(x-2)+10

We multiply parentheses

3x-6+10

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

13x-(3x+4)-14=0

We get rid of parentheses

13x-3x-4-14=0

We add all the numbers together, and all the variables

10x-18=0

We move all terms containing x to the left, all other terms to the right

10x=18

x=18/10

x=1+4/5

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