7(x-2)+8(x-3)=x+10

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Solution for 7(x-2)+8(x-3)=x+10 equation: 



7(x-2)+8(x-3)=x+10

We move all terms to the left:

7(x-2)+8(x-3)-(x+10)=0

We multiply parentheses

7x+8x-(x+10)-14-24=0

We get rid of parentheses

7x+8x-x-10-14-24=0

We add all the numbers together, and all the variables

14x-48=0

We move all terms containing x to the left, all other terms to the right

14x=48

x=48/14

x=3+3/7

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