7(x-2)+8=3(x-4)-2

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Solution for 7(x-2)+8=3(x-4)-2 equation: 



7(x-2)+8=3(x-4)-2

We move all terms to the left:

7(x-2)+8-(3(x-4)-2)=0

We multiply parentheses

7x-(3(x-4)-2)-14+8=0



We calculate terms in parentheses: -(3(x-4)-2), so:

3(x-4)-2

We multiply parentheses

3x-12-2

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

7x-(3x-14)-6=0

We get rid of parentheses

7x-3x+14-6=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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