7(x-2)-3=2(x+2)=10

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Solution for 7(x-2)-3=2(x+2)=10 equation: 



7(x-2)-3=2(x+2)=10

We move all terms to the left:

7(x-2)-3-(2(x+2))=0

We multiply parentheses

7x-(2(x+2))-14-3=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

7x-(2x+4)-17=0

We get rid of parentheses

7x-2x-4-17=0

We add all the numbers together, and all the variables

5x-21=0

We move all terms containing x to the left, all other terms to the right

5x=21

x=21/5

x=4+1/5

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