7(x-2)-4=4(x+1)+8

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Solution for 7(x-2)-4=4(x+1)+8 equation: 



7(x-2)-4=4(x+1)+8

We move all terms to the left:

7(x-2)-4-(4(x+1)+8)=0

We multiply parentheses

7x-(4(x+1)+8)-14-4=0



We calculate terms in parentheses: -(4(x+1)+8), so:

4(x+1)+8

We multiply parentheses

4x+4+8

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

7x-(4x+12)-18=0

We get rid of parentheses

7x-4x-12-18=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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