7(x-2)-6=3(x+2)+10

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Solution for 7(x-2)-6=3(x+2)+10 equation: 



7(x-2)-6=3(x+2)+10

We move all terms to the left:

7(x-2)-6-(3(x+2)+10)=0

We multiply parentheses

7x-(3(x+2)+10)-14-6=0



We calculate terms in parentheses: -(3(x+2)+10), so:

3(x+2)+10

We multiply parentheses

3x+6+10

We add all the numbers together, and all the variables

3x+16

Back to the equation:

-(3x+16)



We add all the numbers together, and all the variables

7x-(3x+16)-20=0

We get rid of parentheses

7x-3x-16-20=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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