7(x-2)-8(4-3x)=2x-1

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Solution for 7(x-2)-8(4-3x)=2x-1 equation: 



7(x-2)-8(4-3x)=2x-1

We move all terms to the left:

7(x-2)-8(4-3x)-(2x-1)=0

We add all the numbers together, and all the variables

7(x-2)-8(-3x+4)-(2x-1)=0

We multiply parentheses

7x+24x-(2x-1)-14-32=0

We get rid of parentheses

7x+24x-2x+1-14-32=0

We add all the numbers together, and all the variables

29x-45=0

We move all terms containing x to the left, all other terms to the right

29x=45

x=45/29

x=1+16/29

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