7(x-2)=-3(x+3)+33

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Solution for 7(x-2)=-3(x+3)+33 equation: 



7(x-2)=-3(x+3)+33

We move all terms to the left:

7(x-2)-(-3(x+3)+33)=0

We multiply parentheses

7x-(-3(x+3)+33)-14=0



We calculate terms in parentheses: -(-3(x+3)+33), so:

-3(x+3)+33

We multiply parentheses

-3x-9+33

We add all the numbers together, and all the variables

-3x+24

Back to the equation:

-(-3x+24)



We get rid of parentheses

7x+3x-24-14=0

We add all the numbers together, and all the variables

10x-38=0

We move all terms containing x to the left, all other terms to the right

10x=38

x=38/10

x=3+4/5

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