7(x-2)=3(x+4)+2

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Solution for 7(x-2)=3(x+4)+2 equation: 



7(x-2)=3(x+4)+2

We move all terms to the left:

7(x-2)-(3(x+4)+2)=0

We multiply parentheses

7x-(3(x+4)+2)-14=0



We calculate terms in parentheses: -(3(x+4)+2), so:

3(x+4)+2

We multiply parentheses

3x+12+2

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We get rid of parentheses

7x-3x-14-14=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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