7(x-2)=4(x+2)+3x-22

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Solution for 7(x-2)=4(x+2)+3x-22 equation: 



7(x-2)=4(x+2)+3x-22

We move all terms to the left:

7(x-2)-(4(x+2)+3x-22)=0

We multiply parentheses

7x-(4(x+2)+3x-22)-14=0



We calculate terms in parentheses: -(4(x+2)+3x-22), so:

4(x+2)+3x-22

We add all the numbers together, and all the variables

3x+4(x+2)-22

We multiply parentheses

3x+4x+8-22

We add all the numbers together, and all the variables

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

7x-7x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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