7(x-2)=5(-x+3)+7

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Solution for 7(x-2)=5(-x+3)+7 equation:



7(x-2)=5(-x+3)+7
We move all terms to the left:
7(x-2)-(5(-x+3)+7)=0
We add all the numbers together, and all the variables
7(x-2)-(5(-1x+3)+7)=0
We multiply parentheses
7x-(5(-1x+3)+7)-14=0
We calculate terms in parentheses: -(5(-1x+3)+7), so:
5(-1x+3)+7
We multiply parentheses
-5x+15+7
We add all the numbers together, and all the variables
-5x+22
Back to the equation:
-(-5x+22)
We get rid of parentheses
7x+5x-22-14=0
We add all the numbers together, and all the variables
12x-36=0
We move all terms containing x to the left, all other terms to the right
12x=36
x=36/12
x=3

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