7(x-2)=5(x+2)+1

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Solution for 7(x-2)=5(x+2)+1 equation: 



7(x-2)=5(x+2)+1

We move all terms to the left:

7(x-2)-(5(x+2)+1)=0

We multiply parentheses

7x-(5(x+2)+1)-14=0



We calculate terms in parentheses: -(5(x+2)+1), so:

5(x+2)+1

We multiply parentheses

5x+10+1

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We get rid of parentheses

7x-5x-11-14=0

We add all the numbers together, and all the variables

2x-25=0

We move all terms containing x to the left, all other terms to the right

2x=25

x=25/2

x=12+1/2

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