7(x-3)+12=8-3(3x-5)

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Solution for 7(x-3)+12=8-3(3x-5) equation: 



7(x-3)+12=8-3(3x-5)

We move all terms to the left:

7(x-3)+12-(8-3(3x-5))=0

We multiply parentheses

7x-(8-3(3x-5))-21+12=0



We calculate terms in parentheses: -(8-3(3x-5)), so:

8-3(3x-5)

determiningTheFunctionDomain
-3(3x-5)+8

We multiply parentheses

-9x+15+8

We add all the numbers together, and all the variables

-9x+23

Back to the equation:

-(-9x+23)



We add all the numbers together, and all the variables

7x-(-9x+23)-9=0

We get rid of parentheses

7x+9x-23-9=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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