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7(x-3)+2=2x+5(-3+x)
We move all terms to the left:
7(x-3)+2-(2x+5(-3+x))=0
We add all the numbers together, and all the variables
7(x-3)-(2x+5(x-3))+2=0
We multiply parentheses
7x-(2x+5(x-3))-21+2=0
We calculate terms in parentheses: -(2x+5(x-3)), so:We add all the numbers together, and all the variables
2x+5(x-3)
We multiply parentheses
2x+5x-15
We add all the numbers together, and all the variables
7x-15
Back to the equation:
-(7x-15)
7x-(7x-15)-19=0
We get rid of parentheses
7x-7x+15-19=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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