7(x-3)+2x+11=12(9x+13)+12x-8

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Solution for 7(x-3)+2x+11=12(9x+13)+12x-8 equation: 



7(x-3)+2x+11=12(9x+13)+12x-8

We move all terms to the left:

7(x-3)+2x+11-(12(9x+13)+12x-8)=0

We add all the numbers together, and all the variables

2x+7(x-3)-(12(9x+13)+12x-8)+11=0

We multiply parentheses

2x+7x-(12(9x+13)+12x-8)-21+11=0



We calculate terms in parentheses: -(12(9x+13)+12x-8), so:

12(9x+13)+12x-8

We add all the numbers together, and all the variables

12x+12(9x+13)-8

We multiply parentheses

12x+108x+156-8

We add all the numbers together, and all the variables

120x+148

Back to the equation:

-(120x+148)



We add all the numbers together, and all the variables

9x-(120x+148)-10=0

We get rid of parentheses

9x-120x-148-10=0

We add all the numbers together, and all the variables

-111x-158=0

We move all terms containing x to the left, all other terms to the right

-111x=158

x=158/-111

x=-1+47/111

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