7(x-3)+8=2(x-4)

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Solution for 7(x-3)+8=2(x-4) equation:


Simplifying
7(x + -3) + 8 = 2(x + -4)

Reorder the terms:
7(-3 + x) + 8 = 2(x + -4)
(-3 * 7 + x * 7) + 8 = 2(x + -4)
(-21 + 7x) + 8 = 2(x + -4)

Reorder the terms:
-21 + 8 + 7x = 2(x + -4)

Combine like terms: -21 + 8 = -13
-13 + 7x = 2(x + -4)

Reorder the terms:
-13 + 7x = 2(-4 + x)
-13 + 7x = (-4 * 2 + x * 2)
-13 + 7x = (-8 + 2x)

Solving
-13 + 7x = -8 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-13 + 7x + -2x = -8 + 2x + -2x

Combine like terms: 7x + -2x = 5x
-13 + 5x = -8 + 2x + -2x

Combine like terms: 2x + -2x = 0
-13 + 5x = -8 + 0
-13 + 5x = -8

Add '13' to each side of the equation.
-13 + 13 + 5x = -8 + 13

Combine like terms: -13 + 13 = 0
0 + 5x = -8 + 13
5x = -8 + 13

Combine like terms: -8 + 13 = 5
5x = 5

Divide each side by '5'.
x = 1

Simplifying
x = 1

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