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7(x-3)+9=5(x-2)-3x
We move all terms to the left:
7(x-3)+9-(5(x-2)-3x)=0
We multiply parentheses
7x-(5(x-2)-3x)-21+9=0
We calculate terms in parentheses: -(5(x-2)-3x), so:We add all the numbers together, and all the variables
5(x-2)-3x
We add all the numbers together, and all the variables
-3x+5(x-2)
We multiply parentheses
-3x+5x-10
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
7x-(2x-10)-12=0
We get rid of parentheses
7x-2x+10-12=0
We add all the numbers together, and all the variables
5x-2=0
We move all terms containing x to the left, all other terms to the right
5x=2
x=2/5
x=2/5
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