7(x-3)+x=8(x-4)+11

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Solution for 7(x-3)+x=8(x-4)+11 equation: 



7(x-3)+x=8(x-4)+11

We move all terms to the left:

7(x-3)+x-(8(x-4)+11)=0

We add all the numbers together, and all the variables

x+7(x-3)-(8(x-4)+11)=0

We multiply parentheses

x+7x-(8(x-4)+11)-21=0



We calculate terms in parentheses: -(8(x-4)+11), so:

8(x-4)+11

We multiply parentheses

8x-32+11

We add all the numbers together, and all the variables

8x-21

Back to the equation:

-(8x-21)



We add all the numbers together, and all the variables

8x-(8x-21)-21=0

We get rid of parentheses

8x-8x+21-21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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