7(x-3)-12=19x-141

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Solution for 7(x-3)-12=19x-141 equation: 



7(x-3)-12=19x-141

We move all terms to the left:

7(x-3)-12-(19x-141)=0

We multiply parentheses

7x-(19x-141)-21-12=0

We get rid of parentheses

7x-19x+141-21-12=0

We add all the numbers together, and all the variables

-12x+108=0

We move all terms containing x to the left, all other terms to the right

-12x=-108

x=-108/-12

x=+9

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