7(x-3)-19=9(x-5)

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Solution for 7(x-3)-19=9(x-5) equation: 



7(x-3)-19=9(x-5)

We move all terms to the left:

7(x-3)-19-(9(x-5))=0

We multiply parentheses

7x-(9(x-5))-21-19=0



We calculate terms in parentheses: -(9(x-5)), so:

9(x-5)

We multiply parentheses

9x-45

Back to the equation:

-(9x-45)



We add all the numbers together, and all the variables

7x-(9x-45)-40=0

We get rid of parentheses

7x-9x+45-40=0

We add all the numbers together, and all the variables

-2x+5=0

We move all terms containing x to the left, all other terms to the right

-2x=-5

x=-5/-2

x=2+1/2

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