7(x-3)-3(x+4)=7+2(3x-8)

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Solution for 7(x-3)-3(x+4)=7+2(3x-8) equation: 



7(x-3)-3(x+4)=7+2(3x-8)

We move all terms to the left:

7(x-3)-3(x+4)-(7+2(3x-8))=0

We multiply parentheses

7x-3x-(7+2(3x-8))-21-12=0



We calculate terms in parentheses: -(7+2(3x-8)), so:

7+2(3x-8)

determiningTheFunctionDomain
2(3x-8)+7

We multiply parentheses

6x-16+7

We add all the numbers together, and all the variables

6x-9

Back to the equation:

-(6x-9)



We add all the numbers together, and all the variables

4x-(6x-9)-33=0

We get rid of parentheses

4x-6x+9-33=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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