7(x-3)-3(x+4)=7+2(3x-8)

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Solution for 7(x-3)-3(x+4)=7+2(3x-8) equation:



7(x-3)-3(x+4)=7+2(3x-8)
We move all terms to the left:
7(x-3)-3(x+4)-(7+2(3x-8))=0
We multiply parentheses
7x-3x-(7+2(3x-8))-21-12=0
We calculate terms in parentheses: -(7+2(3x-8)), so:
7+2(3x-8)
determiningTheFunctionDomain 2(3x-8)+7
We multiply parentheses
6x-16+7
We add all the numbers together, and all the variables
6x-9
Back to the equation:
-(6x-9)
We add all the numbers together, and all the variables
4x-(6x-9)-33=0
We get rid of parentheses
4x-6x+9-33=0
We add all the numbers together, and all the variables
-2x-24=0
We move all terms containing x to the left, all other terms to the right
-2x=24
x=24/-2
x=-12

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