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7(x-3)/2x=3(3x/1)
We move all terms to the left:
7(x-3)/2x-(3(3x/1))=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
7(x-3)/2x-(3(+3x/1))=0
We calculate fractions
7x/2x^2+(-(3(+3x*2x)/2x^2=0
We multiply all the terms by the denominator
7x+(-(3(+3x*2x)=0
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