7(x-3)=-8(x+4)+36

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Solution for 7(x-3)=-8(x+4)+36 equation:



7(x-3)=-8(x+4)+36
We move all terms to the left:
7(x-3)-(-8(x+4)+36)=0
We multiply parentheses
7x-(-8(x+4)+36)-21=0
We calculate terms in parentheses: -(-8(x+4)+36), so:
-8(x+4)+36
We multiply parentheses
-8x-32+36
We add all the numbers together, and all the variables
-8x+4
Back to the equation:
-(-8x+4)
We get rid of parentheses
7x+8x-4-21=0
We add all the numbers together, and all the variables
15x-25=0
We move all terms containing x to the left, all other terms to the right
15x=25
x=25/15
x=1+2/3

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