7(x-3)=10-4(x+5)

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Solution for 7(x-3)=10-4(x+5) equation:



7(x-3)=10-4(x+5)
We move all terms to the left:
7(x-3)-(10-4(x+5))=0
We multiply parentheses
7x-(10-4(x+5))-21=0
We calculate terms in parentheses: -(10-4(x+5)), so:
10-4(x+5)
determiningTheFunctionDomain -4(x+5)+10
We multiply parentheses
-4x-20+10
We add all the numbers together, and all the variables
-4x-10
Back to the equation:
-(-4x-10)
We get rid of parentheses
7x+4x+10-21=0
We add all the numbers together, and all the variables
11x-11=0
We move all terms containing x to the left, all other terms to the right
11x=11
x=11/11
x=1

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