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7(x-3)=3(2-x)
We move all terms to the left:
7(x-3)-(3(2-x))=0
We add all the numbers together, and all the variables
7(x-3)-(3(-1x+2))=0
We multiply parentheses
7x-(3(-1x+2))-21=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
7x+3x-6-21=0
We add all the numbers together, and all the variables
10x-27=0
We move all terms containing x to the left, all other terms to the right
10x=27
x=27/10
x=2+7/10
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