7(x-3)=3(4-x)=-8

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Solution for 7(x-3)=3(4-x)=-8 equation: 



7(x-3)=3(4-x)=-8

We move all terms to the left:

7(x-3)-(3(4-x))=0

We add all the numbers together, and all the variables

7(x-3)-(3(-1x+4))=0

We multiply parentheses

7x-(3(-1x+4))-21=0



We calculate terms in parentheses: -(3(-1x+4)), so:

3(-1x+4)

We multiply parentheses

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

7x+3x-12-21=0

We add all the numbers together, and all the variables

10x-33=0

We move all terms containing x to the left, all other terms to the right

10x=33

x=33/10

x=3+3/10

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