7(x-3)=6(1+x)

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Solution for 7(x-3)=6(1+x) equation: 



7(x-3)=6(1+x)

We move all terms to the left:

7(x-3)-(6(1+x))=0

We add all the numbers together, and all the variables

7(x-3)-(6(x+1))=0

We multiply parentheses

7x-(6(x+1))-21=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

7x-6x-6-21=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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