7(x-3)=6(3x+1)

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Solution for 7(x-3)=6(3x+1) equation: 



7(x-3)=6(3x+1)

We move all terms to the left:

7(x-3)-(6(3x+1))=0

We multiply parentheses

7x-(6(3x+1))-21=0



We calculate terms in parentheses: -(6(3x+1)), so:

6(3x+1)

We multiply parentheses

18x+6

Back to the equation:

-(18x+6)



We get rid of parentheses

7x-18x-6-21=0

We add all the numbers together, and all the variables

-11x-27=0

We move all terms containing x to the left, all other terms to the right

-11x=27

x=27/-11

x=-2+5/11

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