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7(x-3)=8(1+5x)-4x
We move all terms to the left:
7(x-3)-(8(1+5x)-4x)=0
We add all the numbers together, and all the variables
7(x-3)-(8(5x+1)-4x)=0
We multiply parentheses
7x-(8(5x+1)-4x)-21=0
We calculate terms in parentheses: -(8(5x+1)-4x), so:We get rid of parentheses
8(5x+1)-4x
We add all the numbers together, and all the variables
-4x+8(5x+1)
We multiply parentheses
-4x+40x+8
We add all the numbers together, and all the variables
36x+8
Back to the equation:
-(36x+8)
7x-36x-8-21=0
We add all the numbers together, and all the variables
-29x-29=0
We move all terms containing x to the left, all other terms to the right
-29x=29
x=29/-29
x=-1
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