7(x-35)=3(x+2)

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Solution for 7(x-35)=3(x+2) equation: 



7(x-35)=3(x+2)

We move all terms to the left:

7(x-35)-(3(x+2))=0

We multiply parentheses

7x-(3(x+2))-245=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

7x-3x-6-245=0

We add all the numbers together, and all the variables

4x-251=0

We move all terms containing x to the left, all other terms to the right

4x=251

x=251/4

x=62+3/4

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