7(x-4)(x+4)=0

Solution for 7(x-4)(x+4)=0 equation:

Simplifying
7(x + -4)(x + 4) = 0

Reorder the terms:
7(-4 + x)(x + 4) = 0

Reorder the terms:
7(-4 + x)(4 + x) = 0

Multiply (-4 + x) * (4 + x)
7(-4(4 + x) + x(4 + x)) = 0
7((4 * -4 + x * -4) + x(4 + x)) = 0
7((-16 + -4x) + x(4 + x)) = 0
7(-16 + -4x + (4 * x + x * x)) = 0
7(-16 + -4x + (4x + x2)) = 0

Combine like terms: -4x + 4x = 0
7(-16 + 0 + x2) = 0
7(-16 + x2) = 0
(-16 * 7 + x2 * 7) = 0
(-112 + 7x2) = 0

Solving
-112 + 7x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '112' to each side of the equation.
-112 + 112 + 7x2 = 0 + 112

Combine like terms: -112 + 112 = 0
0 + 7x2 = 0 + 112
7x2 = 0 + 112

Combine like terms: 0 + 112 = 112
7x2 = 112

Divide each side by '7'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}