7(x-4)+1=2-(x+3)

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Solution for 7(x-4)+1=2-(x+3) equation: 



7(x-4)+1=2-(x+3)

We move all terms to the left:

7(x-4)+1-(2-(x+3))=0

We multiply parentheses

7x-(2-(x+3))-28+1=0



We calculate terms in parentheses: -(2-(x+3)), so:

2-(x+3)

determiningTheFunctionDomain
-(x+3)+2

We get rid of parentheses

-x-3+2

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

-(-1x-1)



We add all the numbers together, and all the variables

7x-(-1x-1)-27=0

We get rid of parentheses

7x+1x+1-27=0

We add all the numbers together, and all the variables

8x-26=0

We move all terms containing x to the left, all other terms to the right

8x=26

x=26/8

x=3+1/4

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