7(x-4)+2(x-5)=7(x+4)

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Solution for 7(x-4)+2(x-5)=7(x+4) equation: 



7(x-4)+2(x-5)=7(x+4)

We move all terms to the left:

7(x-4)+2(x-5)-(7(x+4))=0

We multiply parentheses

7x+2x-(7(x+4))-28-10=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We add all the numbers together, and all the variables

9x-(7x+28)-38=0

We get rid of parentheses

9x-7x-28-38=0

We add all the numbers together, and all the variables

2x-66=0

We move all terms containing x to the left, all other terms to the right

2x=66

x=66/2

x=33

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