7(x-4)-3(x-2)=6(x+8)

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Solution for 7(x-4)-3(x-2)=6(x+8) equation:



7(x-4)-3(x-2)=6(x+8)
We move all terms to the left:
7(x-4)-3(x-2)-(6(x+8))=0
We multiply parentheses
7x-3x-(6(x+8))-28+6=0
We calculate terms in parentheses: -(6(x+8)), so:
6(x+8)
We multiply parentheses
6x+48
Back to the equation:
-(6x+48)
We add all the numbers together, and all the variables
4x-(6x+48)-22=0
We get rid of parentheses
4x-6x-48-22=0
We add all the numbers together, and all the variables
-2x-70=0
We move all terms containing x to the left, all other terms to the right
-2x=70
x=70/-2
x=-35

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