7(x-4)-8=41

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Solution for 7(x-4)-8=41 equation: 



7(x-4)-8=41

We move all terms to the left:

7(x-4)-8-(41)=0

We add all the numbers together, and all the variables

7(x-4)-49=0

We multiply parentheses

7x-28-49=0

We add all the numbers together, and all the variables

7x-77=0

We move all terms containing x to the left, all other terms to the right

7x=77

x=77/7

x=11

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