7(x-4)=-3(x+2)+33

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Solution for 7(x-4)=-3(x+2)+33 equation: 



7(x-4)=-3(x+2)+33

We move all terms to the left:

7(x-4)-(-3(x+2)+33)=0

We multiply parentheses

7x-(-3(x+2)+33)-28=0



We calculate terms in parentheses: -(-3(x+2)+33), so:

-3(x+2)+33

We multiply parentheses

-3x-6+33

We add all the numbers together, and all the variables

-3x+27

Back to the equation:

-(-3x+27)



We get rid of parentheses

7x+3x-27-28=0

We add all the numbers together, and all the variables

10x-55=0

We move all terms containing x to the left, all other terms to the right

10x=55

x=55/10

x=5+1/2

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